Solve for x
x=\frac{2-8y}{3}
Solve for y
y=-\frac{3x}{8}+\frac{1}{4}
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3x=2-8y
Subtract 8y from both sides.
\frac{3x}{3}=\frac{2-8y}{3}
Divide both sides by 3.
x=\frac{2-8y}{3}
Dividing by 3 undoes the multiplication by 3.
8y=2-3x
Subtract 3x from both sides.
\frac{8y}{8}=\frac{2-3x}{8}
Divide both sides by 8.
y=\frac{2-3x}{8}
Dividing by 8 undoes the multiplication by 8.
y=-\frac{3x}{8}+\frac{1}{4}
Divide 2-3x by 8.
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