Solve for x
x=\frac{-\sin(z)-7y+2}{3}
Solve for y
y=\frac{-\sin(z)-3x+2}{7}
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3x+\sin(z)=2-7y
Subtract 7y from both sides.
3x=2-7y-\sin(z)
Subtract \sin(z) from both sides.
3x=-\sin(z)-7y+2
The equation is in standard form.
\frac{3x}{3}=\frac{-\sin(z)-7y+2}{3}
Divide both sides by 3.
x=\frac{-\sin(z)-7y+2}{3}
Dividing by 3 undoes the multiplication by 3.
7y+\sin(z)=2-3x
Subtract 3x from both sides.
7y=2-3x-\sin(z)
Subtract \sin(z) from both sides.
7y=-\sin(z)-3x+2
The equation is in standard form.
\frac{7y}{7}=\frac{-\sin(z)-3x+2}{7}
Divide both sides by 7.
y=\frac{-\sin(z)-3x+2}{7}
Dividing by 7 undoes the multiplication by 7.
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