Solve for x
x=\frac{4z}{3}-2y+\frac{1}{3}
Solve for y
y=\frac{2z}{3}-\frac{x}{2}+\frac{1}{6}
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3x-4z=1-6y
Subtract 6y from both sides.
3x=1-6y+4z
Add 4z to both sides.
3x=1+4z-6y
The equation is in standard form.
\frac{3x}{3}=\frac{1+4z-6y}{3}
Divide both sides by 3.
x=\frac{1+4z-6y}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{4z}{3}-2y+\frac{1}{3}
Divide 1-6y+4z by 3.
6y-4z=1-3x
Subtract 3x from both sides.
6y=1-3x+4z
Add 4z to both sides.
6y=1+4z-3x
The equation is in standard form.
\frac{6y}{6}=\frac{1+4z-3x}{6}
Divide both sides by 6.
y=\frac{1+4z-3x}{6}
Dividing by 6 undoes the multiplication by 6.
y=\frac{2z}{3}-\frac{x}{2}+\frac{1}{6}
Divide 1-3x+4z by 6.
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