Solve for x
x=\frac{8}{3}-2y
Solve for y
y=-\frac{x}{2}+\frac{4}{3}
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3x=8-6y
Subtract 6y from both sides.
\frac{3x}{3}=\frac{8-6y}{3}
Divide both sides by 3.
x=\frac{8-6y}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{8}{3}-2y
Divide 8-6y by 3.
6y=8-3x
Subtract 3x from both sides.
\frac{6y}{6}=\frac{8-3x}{6}
Divide both sides by 6.
y=\frac{8-3x}{6}
Dividing by 6 undoes the multiplication by 6.
y=-\frac{x}{2}+\frac{4}{3}
Divide 8-3x by 6.
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