Solve 3x+6y+9z+12=15p

$$3 x + 6 y + 9 z + 12 = 15 p$$

Solve for p

$$p=\frac{x+2y+3z+4}{5}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$15p=3x+6y+9z+12$$

Divide both sides by 15.

$$\frac{15p}{15}=\frac{3x+6y+9z+12}{15}$$

Dividing by 15 undoes the multiplication by 15.

$$p=\frac{3x+6y+9z+12}{15}$$

Divide 12+3x+6y+9z by 15.

$$p=\frac{x+2y+3z+4}{5}$$

Solve for x

$$x=-2y-3z+5p-4$$

Steps for Solving Linear Equation

Subtract 6y from both sides.

$$3x+9z+12=15p-6y$$

Subtract 9z from both sides.

$$3x+12=15p-6y-9z$$

Subtract 12 from both sides.

$$3x=15p-6y-9z-12$$

The equation is in standard form.

$$3x=-6y-9z+15p-12$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{-6y-9z+15p-12}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{-6y-9z+15p-12}{3}$$

Divide 15p-6y-9z-12 by 3.

$$x=-2y-3z+5p-4$$