Solve for c
c=\frac{5y}{3}+x
Solve for x
x=-\frac{5y}{3}+c
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3c=3x+5y
Swap sides so that all variable terms are on the left hand side.
\frac{3c}{3}=\frac{3x+5y}{3}
Divide both sides by 3.
c=\frac{3x+5y}{3}
Dividing by 3 undoes the multiplication by 3.
c=\frac{5y}{3}+x
Divide 3x+5y by 3.
3x=3c-5y
Subtract 5y from both sides.
\frac{3x}{3}=\frac{3c-5y}{3}
Divide both sides by 3.
x=\frac{3c-5y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{5y}{3}+c
Divide 3c-5y by 3.
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