Solve for x
x=-\frac{5y}{3}-2z+\frac{1}{3}
Solve for y
y=\frac{1-6z-3x}{5}
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3x+6z=1-5y
Subtract 5y from both sides.
3x=1-5y-6z
Subtract 6z from both sides.
3x=1-6z-5y
The equation is in standard form.
\frac{3x}{3}=\frac{1-6z-5y}{3}
Divide both sides by 3.
x=\frac{1-6z-5y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{5y}{3}-2z+\frac{1}{3}
Divide 1-5y-6z by 3.
5y+6z=1-3x
Subtract 3x from both sides.
5y=1-3x-6z
Subtract 6z from both sides.
5y=1-6z-3x
The equation is in standard form.
\frac{5y}{5}=\frac{1-6z-3x}{5}
Divide both sides by 5.
y=\frac{1-6z-3x}{5}
Dividing by 5 undoes the multiplication by 5.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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