Solve for x
x=-\frac{2z}{3}-\frac{5y}{3}+2
Solve for y
y=\frac{6-2z-3x}{5}
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3x+2z=6-5y
Subtract 5y from both sides.
3x=6-5y-2z
Subtract 2z from both sides.
3x=6-2z-5y
The equation is in standard form.
\frac{3x}{3}=\frac{6-2z-5y}{3}
Divide both sides by 3.
x=\frac{6-2z-5y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{2z}{3}-\frac{5y}{3}+2
Divide 6-5y-2z by 3.
5y+2z=6-3x
Subtract 3x from both sides.
5y=6-3x-2z
Subtract 2z from both sides.
5y=6-2z-3x
The equation is in standard form.
\frac{5y}{5}=\frac{6-2z-3x}{5}
Divide both sides by 5.
y=\frac{6-2z-3x}{5}
Dividing by 5 undoes the multiplication by 5.
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Limits
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