Solve for x
x=-\frac{18}{5y+3}
y\neq -\frac{3}{5}
Solve for y
y=-\frac{3}{5}-\frac{18}{5x}
x\neq 0
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3x+5xy=-18
Subtract 18 from both sides. Anything subtracted from zero gives its negation.
\left(3+5y\right)x=-18
Combine all terms containing x.
\left(5y+3\right)x=-18
The equation is in standard form.
\frac{\left(5y+3\right)x}{5y+3}=-\frac{18}{5y+3}
Divide both sides by 3+5y.
x=-\frac{18}{5y+3}
Dividing by 3+5y undoes the multiplication by 3+5y.
5xy+18=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
5xy=-3x-18
Subtract 18 from both sides.
\frac{5xy}{5x}=\frac{-3x-18}{5x}
Divide both sides by 5x.
y=\frac{-3x-18}{5x}
Dividing by 5x undoes the multiplication by 5x.
y=-\frac{3}{5}-\frac{18}{5x}
Divide -3x-18 by 5x.
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