Solve for x
x=\frac{2+z-4y}{3}
Solve for y
y=\frac{2+z-3x}{4}
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3x-z=2-4y
Subtract 4y from both sides.
3x=2-4y+z
Add z to both sides.
3x=2+z-4y
The equation is in standard form.
\frac{3x}{3}=\frac{2+z-4y}{3}
Divide both sides by 3.
x=\frac{2+z-4y}{3}
Dividing by 3 undoes the multiplication by 3.
4y-z=2-3x
Subtract 3x from both sides.
4y=2-3x+z
Add z to both sides.
4y=2+z-3x
The equation is in standard form.
\frac{4y}{4}=\frac{2+z-3x}{4}
Divide both sides by 4.
y=\frac{2+z-3x}{4}
Dividing by 4 undoes the multiplication by 4.
y=\frac{z}{4}-\frac{3x}{4}+\frac{1}{2}
Divide 2-3x+z by 4.
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