Solve for x
x=\frac{-4y-4}{3}
Solve for y
y=-\frac{3x}{4}-1
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3x+4=-4y
Subtract 4y from both sides. Anything subtracted from zero gives its negation.
3x=-4y-4
Subtract 4 from both sides.
\frac{3x}{3}=\frac{-4y-4}{3}
Divide both sides by 3.
x=\frac{-4y-4}{3}
Dividing by 3 undoes the multiplication by 3.
4y+4=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
4y=-3x-4
Subtract 4 from both sides.
\frac{4y}{4}=\frac{-3x-4}{4}
Divide both sides by 4.
y=\frac{-3x-4}{4}
Dividing by 4 undoes the multiplication by 4.
y=-\frac{3x}{4}-1
Divide -3x-4 by 4.
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Limits
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