Solve 3x+4y+2=0quadA(-2-5)

$$3 x + 4 y + 2 = 0 \quad A ( - 2 - 5 )$$

Solve for x

$$x=\frac{-4y-2}{3}$$

Steps for Solving Linear Equation

Subtract 5 from -2 to get -7.

$$3x+4y+2=0A\left(-7\right)$$

Multiply 0 and -7 to get 0.

$$3x+4y+2=0A$$

Anything times zero gives zero.

$$3x+4y+2=0$$

Subtract 4y from both sides. Anything subtracted from zero gives its negation.

$$3x+2=-4y$$

Subtract 2 from both sides.

$$3x=-4y-2$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{-4y-2}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{-4y-2}{3}$$

Solve for A (complex solution)

$$A\in \mathrm{C}$$

$$x=\frac{-4y-2}{3}$$

Solve for A

$$A\in \mathrm{R}$$

$$x=\frac{-4y-2}{3}$$