Solve for x
x=\frac{10}{3}-y
Solve for y
y=\frac{10}{3}-x
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3x-10=-3y
Subtract 3y from both sides. Anything subtracted from zero gives its negation.
3x=-3y+10
Add 10 to both sides.
3x=10-3y
The equation is in standard form.
\frac{3x}{3}=\frac{10-3y}{3}
Divide both sides by 3.
x=\frac{10-3y}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{10}{3}-y
Divide -3y+10 by 3.
3y-10=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
3y=-3x+10
Add 10 to both sides.
3y=10-3x
The equation is in standard form.
\frac{3y}{3}=\frac{10-3x}{3}
Divide both sides by 3.
y=\frac{10-3x}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{10}{3}-x
Divide -3x+10 by 3.
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