Solve for x
x=\frac{1}{3}-y
Solve for y
y=\frac{1}{3}-x
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3x-1=-3y
Subtract 3y from both sides. Anything subtracted from zero gives its negation.
3x=-3y+1
Add 1 to both sides.
3x=1-3y
The equation is in standard form.
\frac{3x}{3}=\frac{1-3y}{3}
Divide both sides by 3.
x=\frac{1-3y}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{1}{3}-y
Divide -3y+1 by 3.
3y-1=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
3y=-3x+1
Add 1 to both sides.
3y=1-3x
The equation is in standard form.
\frac{3y}{3}=\frac{1-3x}{3}
Divide both sides by 3.
y=\frac{1-3x}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{1}{3}-x
Divide -3x+1 by 3.
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