Solve for x
x=-\frac{2y}{3}+2z+\frac{7}{3}
Solve for y
y=-\frac{3x}{2}+3z+\frac{7}{2}
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3x-6z=7-2y
Subtract 2y from both sides.
3x=7-2y+6z
Add 6z to both sides.
3x=7+6z-2y
The equation is in standard form.
\frac{3x}{3}=\frac{7+6z-2y}{3}
Divide both sides by 3.
x=\frac{7+6z-2y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{2y}{3}+2z+\frac{7}{3}
Divide 7-2y+6z by 3.
2y-6z=7-3x
Subtract 3x from both sides.
2y=7-3x+6z
Add 6z to both sides.
2y=7+6z-3x
The equation is in standard form.
\frac{2y}{2}=\frac{7+6z-3x}{2}
Divide both sides by 2.
y=\frac{7+6z-3x}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{3x}{2}+3z+\frac{7}{2}
Divide 7-3x+6z by 2.
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