Solve 3x+2y^2+56=100

$$3 x + 2 y ^ { 2 } + 56 = 100$$

Solve for x

$$x=\frac{44-2y^{2}}{3}$$

Steps for Solving Linear Equation

Subtract 2y^{2} from both sides.

$$3x+56=100-2y^{2}$$

Subtract 56 from both sides.

$$3x=100-2y^{2}-56$$

Subtract 56 from 100 to get 44.

$$3x=44-2y^{2}$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{44-2y^{2}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{44-2y^{2}}{3}$$

Solve for y (complex solution)

$$y=-\frac{\sqrt{88-6x}}{2}$$

$$y=\frac{\sqrt{88-6x}}{2}$$

Solve for y

$$y=\frac{\sqrt{88-6x}}{2}$$

$$y=-\frac{\sqrt{88-6x}}{2}\text{, }x\leq \frac{44}{3}$$