Solve 3x+2y^2+5=120

$$3 x + 2 y ^ { 2 } + 5 = 120$$

Solve for x

$$x=\frac{115-2y^{2}}{3}$$

Steps for Solving Linear Equation

Subtract 2y^{2} from both sides.

$$3x+5=120-2y^{2}$$

Subtract 5 from both sides.

$$3x=120-2y^{2}-5$$

Subtract 5 from 120 to get 115.

$$3x=115-2y^{2}$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{115-2y^{2}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{115-2y^{2}}{3}$$

Solve for y (complex solution)

$$y=-\frac{\sqrt{230-6x}}{2}$$

$$y=\frac{\sqrt{230-6x}}{2}$$

Solve for y

$$y=\frac{\sqrt{230-6x}}{2}$$

$$y=-\frac{\sqrt{230-6x}}{2}\text{, }x\leq \frac{115}{3}$$