Solve for x
x=\frac{8-2y}{3}
Solve for y
y=-\frac{3x}{2}+4
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3x=8-2y
Subtract 2y from both sides.
\frac{3x}{3}=\frac{8-2y}{3}
Divide both sides by 3.
x=\frac{8-2y}{3}
Dividing by 3 undoes the multiplication by 3.
2y=8-3x
Subtract 3x from both sides.
\frac{2y}{2}=\frac{8-3x}{2}
Divide both sides by 2.
y=\frac{8-3x}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{3x}{2}+4
Divide 8-3x by 2.
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