3 x + 2 y = 6 \sum \xi
Solve for x
x=2Σ\xi -\frac{2y}{3}
Solve for y
y=3Σ\xi -\frac{3x}{2}
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3x=6Σ\xi -2y
Subtract 2y from both sides.
\frac{3x}{3}=\frac{6Σ\xi -2y}{3}
Divide both sides by 3.
x=\frac{6Σ\xi -2y}{3}
Dividing by 3 undoes the multiplication by 3.
x=2Σ\xi -\frac{2y}{3}
Divide 6Σ\xi -2y by 3.
2y=6Σ\xi -3x
Subtract 3x from both sides.
\frac{2y}{2}=\frac{6Σ\xi -3x}{2}
Divide both sides by 2.
y=\frac{6Σ\xi -3x}{2}
Dividing by 2 undoes the multiplication by 2.
y=3Σ\xi -\frac{3x}{2}
Divide 6Σ\xi -3x by 2.
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