Solve for x
x=\frac{16-2y}{3}
Solve for y
y=-\frac{3x}{2}+8
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3x+4=20-2y
Subtract 2y from both sides.
3x=20-2y-4
Subtract 4 from both sides.
3x=16-2y
Subtract 4 from 20 to get 16.
\frac{3x}{3}=\frac{16-2y}{3}
Divide both sides by 3.
x=\frac{16-2y}{3}
Dividing by 3 undoes the multiplication by 3.
2y+4=20-3x
Subtract 3x from both sides.
2y=20-3x-4
Subtract 4 from both sides.
2y=16-3x
Subtract 4 from 20 to get 16.
\frac{2y}{2}=\frac{16-3x}{2}
Divide both sides by 2.
y=\frac{16-3x}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{3x}{2}+8
Divide 16-3x by 2.
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