Type a math problem  Factor Solution Steps
Factor out .
Consider . Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
Factor the expression by grouping. First, the expression needs to be rewritten as . To find and , set up a system to be solved.
Since is negative, and have the opposite signs. Since is positive, the positive number has greater absolute value than the negative. The only such pair is the system solution.
Rewrite as .
Factor out in the first and in the second group.
Factor out common term by using distributive property.
Rewrite the complete factored expression.
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x\left(3+2x-x^{2}\right)
Factor out x.
-x^{2}+2x+3
Consider 3+2x-x^{2}. Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=2 ab=-3=-3
Factor the expression by grouping. First, the expression needs to be rewritten as -x^{2}+ax+bx+3. To find a and b, set up a system to be solved.
a=3 b=-1
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. The only such pair is the system solution.
\left(-x^{2}+3x\right)+\left(-x+3\right)
Rewrite -x^{2}+2x+3 as \left(-x^{2}+3x\right)+\left(-x+3\right).
-x\left(x-3\right)-\left(x-3\right)
Factor out -x in the first and -1 in the second group.
\left(x-3\right)\left(-x-1\right)
Factor out common term x-3 by using distributive property.
x\left(x-3\right)\left(-x-1\right)
Rewrite the complete factored expression.