Solve for x
x\leq 1
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3x+11-6x\geq 8
Subtract 6x from both sides.
-3x+11\geq 8
Combine 3x and -6x to get -3x.
-3x\geq 8-11
Subtract 11 from both sides.
-3x\geq -3
Subtract 11 from 8 to get -3.
x\leq \frac{-3}{-3}
Divide both sides by -3. Since -3 is negative, the inequality direction is changed.
x\leq 1
Divide -3 by -3 to get 1.
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