Solve for x
x=\frac{40-10y}{3}
Solve for y
y=-\frac{3x}{10}+4
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3x=40-10y
Subtract 10y from both sides.
\frac{3x}{3}=\frac{40-10y}{3}
Divide both sides by 3.
x=\frac{40-10y}{3}
Dividing by 3 undoes the multiplication by 3.
10y=40-3x
Subtract 3x from both sides.
\frac{10y}{10}=\frac{40-3x}{10}
Divide both sides by 10.
y=\frac{40-3x}{10}
Dividing by 10 undoes the multiplication by 10.
y=-\frac{3x}{10}+4
Divide 40-3x by 10.
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