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3x_{7}y=84,10y+3x=102
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
3x_{7}y=84
Pick one of the two equations which is more simple to solve for y by isolating y on the left hand side of the equal sign.
y=\frac{28}{x_{7}}
Divide both sides by 3x_{7}.
10\times \frac{28}{x_{7}}+3x=102
Substitute \frac{28}{x_{7}} for y in the other equation, 10y+3x=102.
\frac{280}{x_{7}}+3x=102
Multiply 10 times \frac{28}{x_{7}}.
3x=102-\frac{280}{x_{7}}
Subtract \frac{280}{x_{7}} from both sides of the equation.
x=34-\frac{280}{3x_{7}}
Divide both sides by 3.
y=\frac{28}{x_{7}},x=34-\frac{280}{3x_{7}}
The system is now solved.