Solve for x
x=\frac{19-y}{3}
Solve for y
y=19-3x
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3x-19=-y
Subtract 1y from both sides. Anything subtracted from zero gives its negation.
3x=-y+19
Add 19 to both sides.
3x=19-y
The equation is in standard form.
\frac{3x}{3}=\frac{19-y}{3}
Divide both sides by 3.
x=\frac{19-y}{3}
Dividing by 3 undoes the multiplication by 3.
1y-19=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
1y=-3x+19
Add 19 to both sides.
y=-3x+19
Reorder the terms.
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