Solve 3x+1geq7x-5

$$3 x + 1 \geq 7 x - 5$$

Solve for x

$$x\leq \frac{3}{2}$$

Solution Steps

Subtract 7x from both sides.

$$3x+1-7x\geq -5$$

Combine 3x and -7x to get -4x.

$$-4x+1\geq -5$$

Subtract 1 from both sides.

$$-4x\geq -5-1$$

Subtract 1 from -5 to get -6.

$$-4x\geq -6$$

Divide both sides by -4. Since -4 is negative, the inequality direction is changed.

$$x\leq \frac{-6}{-4}$$

Reduce the fraction \frac{-6}{-4} to lowest terms by extracting and canceling out -2.

$$x\leq \frac{3}{2}$$