Solve for x
x=\frac{-2\sqrt{5}-1}{3}\approx -1.824045318
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3x+1=-2\sqrt{5}
Factor 20=2^{2}\times 5. Rewrite the square root of the product \sqrt{2^{2}\times 5} as the product of square roots \sqrt{2^{2}}\sqrt{5}. Take the square root of 2^{2}.
3x=-2\sqrt{5}-1
Subtract 1 from both sides.
\frac{3x}{3}=\frac{-2\sqrt{5}-1}{3}
Divide both sides by 3.
x=\frac{-2\sqrt{5}-1}{3}
Dividing by 3 undoes the multiplication by 3.
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