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3xy+8=2y
Multiply both sides of the equation by y.
3xy=2y-8
Subtract 8 from both sides.
3yx=2y-8
The equation is in standard form.
\frac{3yx}{3y}=\frac{2y-8}{3y}
Divide both sides by 3y.
x=\frac{2y-8}{3y}
Dividing by 3y undoes the multiplication by 3y.
x=\frac{2}{3}-\frac{8}{3y}
Divide -8+2y by 3y.
3xy+8=2y
Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by y.
3xy+8-2y=0
Subtract 2y from both sides.
3xy-2y=-8
Subtract 8 from both sides. Anything subtracted from zero gives its negation.
\left(3x-2\right)y=-8
Combine all terms containing y.
\frac{\left(3x-2\right)y}{3x-2}=-\frac{8}{3x-2}
Divide both sides by 3x-2.
y=-\frac{8}{3x-2}
Dividing by 3x-2 undoes the multiplication by 3x-2.
y=-\frac{8}{3x-2}\text{, }y\neq 0
Variable y cannot be equal to 0.