Solve 3x+3/5-8x=3x+3

$$3 x + \frac { 3 } { 5 } - 8 x = 3 x + 3$$

Solve for x

$$x=-\frac{3}{10}=-0.3$$

Steps for Solving Linear Equation

Combine 3x and -8x to get -5x.

$$-5x+\frac{3}{5}=3x+3$$

Subtract 3x from both sides.

$$-5x+\frac{3}{5}-3x=3$$

Combine -5x and -3x to get -8x.

$$-8x+\frac{3}{5}=3$$

Subtract \frac{3}{5} from both sides.

$$-8x=3-\frac{3}{5}$$

Convert 3 to fraction \frac{15}{5}.

$$-8x=\frac{15}{5}-\frac{3}{5}$$

Since \frac{15}{5} and \frac{3}{5} have the same denominator, subtract them by subtracting their numerators.

$$-8x=\frac{15-3}{5}$$

Subtract 3 from 15 to get 12.

$$-8x=\frac{12}{5}$$

Divide both sides by -8.

$$x=\frac{\frac{12}{5}}{-8}$$

Express \frac{\frac{12}{5}}{-8} as a single fraction.

$$x=\frac{12}{5\left(-8\right)}$$

Multiply 5 and -8 to get -40.

$$x=\frac{12}{-40}$$

Reduce the fraction \frac{12}{-40} to lowest terms by extracting and canceling out 4.

$$x=-\frac{3}{10}$$