Solve 3x+19/4=7

$$3 x + \frac { 19 } { 4 } = 7$$

Solve for x

$$x=\frac{3}{4}=0.75$$

Steps for Solving Linear Equation

Subtract \frac{19}{4} from both sides.

$$3x=7-\frac{19}{4}$$

Convert 7 to fraction \frac{28}{4}.

$$3x=\frac{28}{4}-\frac{19}{4}$$

Since \frac{28}{4} and \frac{19}{4} have the same denominator, subtract them by subtracting their numerators.

$$3x=\frac{28-19}{4}$$

Subtract 19 from 28 to get 9.

$$3x=\frac{9}{4}$$

Divide both sides by 3.

$$x=\frac{\frac{9}{4}}{3}$$

Express \frac{\frac{9}{4}}{3} as a single fraction.

$$x=\frac{9}{4\times 3}$$

Multiply 4 and 3 to get 12.

$$x=\frac{9}{12}$$

Reduce the fraction \frac{9}{12} to lowest terms by extracting and canceling out 3.

$$x=\frac{3}{4}$$