Solve 3x+1/2y=-2

$$3 x + \frac { 1 } { 2 } y = - 2$$

Solve for x

$$x=-\frac{y}{6}-\frac{2}{3}$$

Steps for Solving Linear Equation

Subtract \frac{1}{2}y from both sides.

$$3x=-2-\frac{1}{2}y$$

The equation is in standard form.

$$3x=-\frac{y}{2}-2$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{-\frac{y}{2}-2}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{-\frac{y}{2}-2}{3}$$

Divide -2-\frac{y}{2} by 3.

$$x=-\frac{y}{6}-\frac{2}{3}$$

Solve for y

$$y=-6x-4$$

Steps for Solving Linear Equation

Subtract 3x from both sides.

$$\frac{1}{2}y=-2-3x$$

The equation is in standard form.

$$\frac{1}{2}y=-3x-2$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}y}{\frac{1}{2}}=\frac{-3x-2}{\frac{1}{2}}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$y=\frac{-3x-2}{\frac{1}{2}}$$

Divide -2-3x by \frac{1}{2} by multiplying -2-3x by the reciprocal of \frac{1}{2}.

$$y=-6x-4$$