Factor
3\left(w-4\right)\left(w^{2}+4w+16\right)
Evaluate
3\left(w^{3}-64\right)
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3\left(w^{3}-64\right)
Factor out 3.
\left(w-4\right)\left(w^{2}+4w+16\right)
Consider w^{3}-64. Rewrite w^{3}-64 as w^{3}-4^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
3\left(w-4\right)\left(w^{2}+4w+16\right)
Rewrite the complete factored expression. Polynomial w^{2}+4w+16 is not factored since it does not have any rational roots.
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