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3u^{2}=-2
Subtract 2 from both sides. Anything subtracted from zero gives its negation.
u^{2}=-\frac{2}{3}
Divide both sides by 3.
u=\frac{\sqrt{6}i}{3} u=-\frac{\sqrt{6}i}{3}
The equation is now solved.
3u^{2}+2=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
u=\frac{0±\sqrt{0^{2}-4\times 3\times 2}}{2\times 3}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, 0 for b, and 2 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
u=\frac{0±\sqrt{-4\times 3\times 2}}{2\times 3}
Square 0.
u=\frac{0±\sqrt{-12\times 2}}{2\times 3}
Multiply -4 times 3.
u=\frac{0±\sqrt{-24}}{2\times 3}
Multiply -12 times 2.
u=\frac{0±2\sqrt{6}i}{2\times 3}
Take the square root of -24.
u=\frac{0±2\sqrt{6}i}{6}
Multiply 2 times 3.
u=\frac{\sqrt{6}i}{3}
Now solve the equation u=\frac{0±2\sqrt{6}i}{6} when ± is plus.
u=-\frac{\sqrt{6}i}{3}
Now solve the equation u=\frac{0±2\sqrt{6}i}{6} when ± is minus.
u=\frac{\sqrt{6}i}{3} u=-\frac{\sqrt{6}i}{3}
The equation is now solved.