Factor
3\left(p-3\right)\left(p^{2}+3p+9\right)
Evaluate
3\left(p^{3}-27\right)
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3\left(p^{3}-27\right)
Factor out 3.
\left(p-3\right)\left(p^{2}+3p+9\right)
Consider p^{3}-27. Rewrite p^{3}-27 as p^{3}-3^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
3\left(p-3\right)\left(p^{2}+3p+9\right)
Rewrite the complete factored expression. Polynomial p^{2}+3p+9 is not factored since it does not have any rational roots.
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