Solve 3n(2*2^3)=-412/399

$$3 n ( 2 \cdot 2 ^ { 3 } ) = - 4 \frac { 12 } { 399 }$$

Solve for n

$$n=-\frac{67}{798}\approx -0.0839599$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 399.

$$1197n\times 2\times 2^{3}=-\left(4\times 399+12\right)$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$1197n\times 2^{4}=-\left(4\times 399+12\right)$$

Calculate 2 to the power of 4 and get 16.

$$1197n\times 16=-\left(4\times 399+12\right)$$

Multiply 1197 and 16 to get 19152.

$$19152n=-\left(4\times 399+12\right)$$

Multiply 4 and 399 to get 1596.

$$19152n=-\left(1596+12\right)$$

Add 1596 and 12 to get 1608.

$$19152n=-1608$$

Divide both sides by 19152.

$$n=\frac{-1608}{19152}$$

Reduce the fraction \frac{-1608}{19152} to lowest terms by extracting and canceling out 24.

$$n=-\frac{67}{798}$$