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a+b=-7 ab=3\left(-370\right)=-1110
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as 3n^{2}+an+bn-370. To find a and b, set up a system to be solved.
1,-1110 2,-555 3,-370 5,-222 6,-185 10,-111 15,-74 30,-37
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -1110.
1-1110=-1109 2-555=-553 3-370=-367 5-222=-217 6-185=-179 10-111=-101 15-74=-59 30-37=-7
Calculate the sum for each pair.
a=-37 b=30
The solution is the pair that gives sum -7.
\left(3n^{2}-37n\right)+\left(30n-370\right)
Rewrite 3n^{2}-7n-370 as \left(3n^{2}-37n\right)+\left(30n-370\right).
n\left(3n-37\right)+10\left(3n-37\right)
Factor out n in the first and 10 in the second group.
\left(3n-37\right)\left(n+10\right)
Factor out common term 3n-37 by using distributive property.
n=\frac{37}{3} n=-10
To find equation solutions, solve 3n-37=0 and n+10=0.
3n^{2}-7n-370=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
n=\frac{-\left(-7\right)±\sqrt{\left(-7\right)^{2}-4\times 3\left(-370\right)}}{2\times 3}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, -7 for b, and -370 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
n=\frac{-\left(-7\right)±\sqrt{49-4\times 3\left(-370\right)}}{2\times 3}
Square -7.
n=\frac{-\left(-7\right)±\sqrt{49-12\left(-370\right)}}{2\times 3}
Multiply -4 times 3.
n=\frac{-\left(-7\right)±\sqrt{49+4440}}{2\times 3}
Multiply -12 times -370.
n=\frac{-\left(-7\right)±\sqrt{4489}}{2\times 3}
Add 49 to 4440.
n=\frac{-\left(-7\right)±67}{2\times 3}
Take the square root of 4489.
n=\frac{7±67}{2\times 3}
The opposite of -7 is 7.
n=\frac{7±67}{6}
Multiply 2 times 3.
n=\frac{74}{6}
Now solve the equation n=\frac{7±67}{6} when ± is plus. Add 7 to 67.
n=\frac{37}{3}
Reduce the fraction \frac{74}{6} to lowest terms by extracting and canceling out 2.
n=-\frac{60}{6}
Now solve the equation n=\frac{7±67}{6} when ± is minus. Subtract 67 from 7.
n=-10
Divide -60 by 6.
n=\frac{37}{3} n=-10
The equation is now solved.
3n^{2}-7n-370=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
3n^{2}-7n-370-\left(-370\right)=-\left(-370\right)
Add 370 to both sides of the equation.
3n^{2}-7n=-\left(-370\right)
Subtracting -370 from itself leaves 0.
3n^{2}-7n=370
Subtract -370 from 0.
\frac{3n^{2}-7n}{3}=\frac{370}{3}
Divide both sides by 3.
n^{2}-\frac{7}{3}n=\frac{370}{3}
Dividing by 3 undoes the multiplication by 3.
n^{2}-\frac{7}{3}n+\left(-\frac{7}{6}\right)^{2}=\frac{370}{3}+\left(-\frac{7}{6}\right)^{2}
Divide -\frac{7}{3}, the coefficient of the x term, by 2 to get -\frac{7}{6}. Then add the square of -\frac{7}{6} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
n^{2}-\frac{7}{3}n+\frac{49}{36}=\frac{370}{3}+\frac{49}{36}
Square -\frac{7}{6} by squaring both the numerator and the denominator of the fraction.
n^{2}-\frac{7}{3}n+\frac{49}{36}=\frac{4489}{36}
Add \frac{370}{3} to \frac{49}{36} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(n-\frac{7}{6}\right)^{2}=\frac{4489}{36}
Factor n^{2}-\frac{7}{3}n+\frac{49}{36}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(n-\frac{7}{6}\right)^{2}}=\sqrt{\frac{4489}{36}}
Take the square root of both sides of the equation.
n-\frac{7}{6}=\frac{67}{6} n-\frac{7}{6}=-\frac{67}{6}
Simplify.
n=\frac{37}{3} n=-10
Add \frac{7}{6} to both sides of the equation.
x ^ 2 -\frac{7}{3}x -\frac{370}{3} = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 3
r + s = \frac{7}{3} rs = -\frac{370}{3}
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = \frac{7}{6} - u s = \frac{7}{6} + u
Two numbers r and s sum up to \frac{7}{3} exactly when the average of the two numbers is \frac{1}{2}*\frac{7}{3} = \frac{7}{6}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(\frac{7}{6} - u) (\frac{7}{6} + u) = -\frac{370}{3}
To solve for unknown quantity u, substitute these in the product equation rs = -\frac{370}{3}
\frac{49}{36} - u^2 = -\frac{370}{3}
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -\frac{370}{3}-\frac{49}{36} = -\frac{4489}{36}
Simplify the expression by subtracting \frac{49}{36} on both sides
u^2 = \frac{4489}{36} u = \pm\sqrt{\frac{4489}{36}} = \pm \frac{67}{6}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =\frac{7}{6} - \frac{67}{6} = -10 s = \frac{7}{6} + \frac{67}{6} = 12.333
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.