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m\left(3m-6\right)=0
Factor out m.
m=0 m=2
To find equation solutions, solve m=0 and 3m-6=0.
3m^{2}-6m=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
m=\frac{-\left(-6\right)±\sqrt{\left(-6\right)^{2}}}{2\times 3}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, -6 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
m=\frac{-\left(-6\right)±6}{2\times 3}
Take the square root of \left(-6\right)^{2}.
m=\frac{6±6}{2\times 3}
The opposite of -6 is 6.
m=\frac{6±6}{6}
Multiply 2 times 3.
m=\frac{12}{6}
Now solve the equation m=\frac{6±6}{6} when ± is plus. Add 6 to 6.
m=2
Divide 12 by 6.
m=\frac{0}{6}
Now solve the equation m=\frac{6±6}{6} when ± is minus. Subtract 6 from 6.
m=0
Divide 0 by 6.
m=2 m=0
The equation is now solved.
3m^{2}-6m=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{3m^{2}-6m}{3}=\frac{0}{3}
Divide both sides by 3.
m^{2}+\left(-\frac{6}{3}\right)m=\frac{0}{3}
Dividing by 3 undoes the multiplication by 3.
m^{2}-2m=\frac{0}{3}
Divide -6 by 3.
m^{2}-2m=0
Divide 0 by 3.
m^{2}-2m+1=1
Divide -2, the coefficient of the x term, by 2 to get -1. Then add the square of -1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
\left(m-1\right)^{2}=1
Factor m^{2}-2m+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(m-1\right)^{2}}=\sqrt{1}
Take the square root of both sides of the equation.
m-1=1 m-1=-1
Simplify.
m=2 m=0
Add 1 to both sides of the equation.