Solve 3g-2c+3b/2

$$3 g - 2 c + \frac { 3 b } { 2 }$$

Evaluate

$$\frac{3b}{2}+3g-2c$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 3g-2c times \frac{2}{2}.

$$\frac{2\left(3g-2c\right)}{2}+\frac{3b}{2}$$

Since \frac{2\left(3g-2c\right)}{2} and \frac{3b}{2} have the same denominator, add them by adding their numerators.

$$\frac{2\left(3g-2c\right)+3b}{2}$$

Do the multiplications in 2\left(3g-2c\right)+3b.

$$\frac{6g-4c+3b}{2}$$

Factor

$$\frac{3b-4c+6g}{2}$$

Solution Steps

Factor out \frac{1}{2}.

$$\frac{6g-4c+3b}{2}$$