Solve for f (complex solution)
f=-\frac{-4\cos(x)+xy}{3x}
x\neq 0
Solve for f
f=\frac{\frac{4\cos(x)}{x}-y}{3}
x\neq 0
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3fx+yx=4\cos(x)
Combine 2x and -x to get x.
3fx=4\cos(x)-yx
Subtract yx from both sides.
3xf=4\cos(x)-xy
The equation is in standard form.
\frac{3xf}{3x}=\frac{4\cos(x)-xy}{3x}
Divide both sides by 3x.
f=\frac{4\cos(x)-xy}{3x}
Dividing by 3x undoes the multiplication by 3x.
f=\frac{\frac{4\cos(x)}{x}-y}{3}
Divide 4\cos(x)-yx by 3x.
3fx+yx=4\cos(x)
Combine 2x and -x to get x.
3fx=4\cos(x)-yx
Subtract yx from both sides.
3xf=4\cos(x)-xy
The equation is in standard form.
\frac{3xf}{3x}=\frac{4\cos(x)-xy}{3x}
Divide both sides by 3x.
f=\frac{4\cos(x)-xy}{3x}
Dividing by 3x undoes the multiplication by 3x.
f=\frac{\frac{4\cos(x)}{x}-y}{3}
Divide 4\cos(x)-yx by 3x.
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