Factor
3\left(c-4\right)\left(c^{2}+4c+16\right)
Evaluate
3\left(c^{3}-64\right)
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3\left(c^{3}-64\right)
Factor out 3.
\left(c-4\right)\left(c^{2}+4c+16\right)
Consider c^{3}-64. Rewrite c^{3}-64 as c^{3}-4^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
3\left(c-4\right)\left(c^{2}+4c+16\right)
Rewrite the complete factored expression. Polynomial c^{2}+4c+16 is not factored since it does not have any rational roots.
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