Solve 3b-4b+3+6b

$$3 b - 4 b + 3 + 6 b$$

Evaluate

$$5b+3$$

Solution Steps

Combine 3b and -4b to get -b.

$$-b+3+6b$$

Combine -b and 6b to get 5b.

$$5b+3$$

Differentiate w.r.t. b

$$5$$

Steps Using Derivative Rule for Sum

Combine 3b and -4b to get -b.

$$\frac{\mathrm{d}}{\mathrm{d}b}(-b+3+6b)$$

Combine -b and 6b to get 5b.

$$\frac{\mathrm{d}}{\mathrm{d}b}(5b+3)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$5b^{1-1}$$

Subtract 1 from 1.

$$5b^{0}$$

For any term t except 0, t^{0}=1.

$$5\times 1$$

For any term t, t\times 1=t and 1t=t.

$$5$$