Solve 3b-9b/b+3=

$$3 b - \frac { 9 b } { b + 3 } =$$

Evaluate

$$\frac{3b^{2}}{b+3}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 3b times \frac{b+3}{b+3}.

$$\frac{3b\left(b+3\right)}{b+3}-\frac{9b}{b+3}$$

Since \frac{3b\left(b+3\right)}{b+3} and \frac{9b}{b+3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3b\left(b+3\right)-9b}{b+3}$$

Do the multiplications in 3b\left(b+3\right)-9b.

$$\frac{3b^{2}+9b-9b}{b+3}$$

Combine like terms in 3b^{2}+9b-9b.

$$\frac{3b^{2}}{b+3}$$

Factor

$$\frac{3b^{2}}{b+3}$$