Factor
3\left(b-4\right)\left(b^{2}+4b+16\right)
Evaluate
3\left(b^{3}-64\right)
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3\left(b^{3}-64\right)
Factor out 3.
\left(b-4\right)\left(b^{2}+4b+16\right)
Consider b^{3}-64. Rewrite b^{3}-64 as b^{3}-4^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right).
3\left(b-4\right)\left(b^{2}+4b+16\right)
Rewrite the complete factored expression. Polynomial b^{2}+4b+16 is not factored since it does not have any rational roots.
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