Solve 3b+5a=xab

$$3 b + 5 a = x a b$$

Solve for a

$$a=-\frac{3b}{5-bx}$$

$$x=0\text{ or }b\neq \frac{5}{x}$$

Steps for Solving Linear Equation

Subtract xab from both sides.

$$3b+5a-xab=0$$

Subtract 3b from both sides. Anything subtracted from zero gives its negation.

$$5a-xab=-3b$$

Combine all terms containing a.

$$\left(5-xb\right)a=-3b$$

The equation is in standard form.

$$\left(5-bx\right)a=-3b$$

Divide both sides by 5-xb.

$$\frac{\left(5-bx\right)a}{5-bx}=-\frac{3b}{5-bx}$$

Dividing by 5-xb undoes the multiplication by 5-xb.

$$a=-\frac{3b}{5-bx}$$

Solve for b

$$b=-\frac{5a}{3-ax}$$

$$x=0\text{ or }a\neq \frac{3}{x}$$

Steps for Solving Linear Equation

Subtract xab from both sides.

$$3b+5a-xab=0$$

Subtract 5a from both sides. Anything subtracted from zero gives its negation.

$$3b-xab=-5a$$

Combine all terms containing b.

$$\left(3-xa\right)b=-5a$$

The equation is in standard form.

$$\left(3-ax\right)b=-5a$$

Divide both sides by 3-xa.

$$\frac{\left(3-ax\right)b}{3-ax}=-\frac{5a}{3-ax}$$

Dividing by 3-xa undoes the multiplication by 3-xa.

$$b=-\frac{5a}{3-ax}$$