Solve 3b+5-12b-6=

$$3 b + 5 - 12 b - 6 =$$

Evaluate

$$-9b-1$$

Solution Steps

Combine 3b and -12b to get -9b.

$$-9b+5-6$$

Subtract 6 from 5 to get -1.

$$-9b-1$$

Differentiate w.r.t. b

$$-9$$

Steps Using Derivative Rule for Sum

Combine 3b and -12b to get -9b.

$$\frac{\mathrm{d}}{\mathrm{d}b}(-9b+5-6)$$

Subtract 6 from 5 to get -1.

$$\frac{\mathrm{d}}{\mathrm{d}b}(-9b-1)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-9b^{1-1}$$

Subtract 1 from 1.

$$-9b^{0}$$

For any term t except 0, t^{0}=1.

$$-9$$