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Solve for a (complex solution)
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Solve for b (complex solution)
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Solve for a
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Solve for b
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3ax-b+3a=bx
Add 3a to both sides.
3ax+3a=bx+b
Add b to both sides.
\left(3x+3\right)a=bx+b
Combine all terms containing a.
\frac{\left(3x+3\right)a}{3x+3}=\frac{bx+b}{3x+3}
Divide both sides by 3x+3.
a=\frac{bx+b}{3x+3}
Dividing by 3x+3 undoes the multiplication by 3x+3.
a=\frac{b}{3}
Divide bx+b by 3x+3.
3ax-b-bx=-3a
Subtract bx from both sides.
-b-bx=-3a-3ax
Subtract 3ax from both sides.
\left(-1-x\right)b=-3a-3ax
Combine all terms containing b.
\left(-x-1\right)b=-3ax-3a
The equation is in standard form.
\frac{\left(-x-1\right)b}{-x-1}=\frac{-3ax-3a}{-x-1}
Divide both sides by -1-x.
b=\frac{-3ax-3a}{-x-1}
Dividing by -1-x undoes the multiplication by -1-x.
b=3a
Divide -3a-3ax by -1-x.
3ax-b+3a=bx
Add 3a to both sides.
3ax+3a=bx+b
Add b to both sides.
\left(3x+3\right)a=bx+b
Combine all terms containing a.
\frac{\left(3x+3\right)a}{3x+3}=\frac{bx+b}{3x+3}
Divide both sides by 3x+3.
a=\frac{bx+b}{3x+3}
Dividing by 3x+3 undoes the multiplication by 3x+3.
a=\frac{b}{3}
Divide bx+b by 3x+3.
3ax-b-bx=-3a
Subtract bx from both sides.
-b-bx=-3a-3ax
Subtract 3ax from both sides.
\left(-1-x\right)b=-3a-3ax
Combine all terms containing b.
\left(-x-1\right)b=-3ax-3a
The equation is in standard form.
\frac{\left(-x-1\right)b}{-x-1}=\frac{-3ax-3a}{-x-1}
Divide both sides by -1-x.
b=\frac{-3ax-3a}{-x-1}
Dividing by -1-x undoes the multiplication by -1-x.
b=3a
Divide -3a-3ax by -1-x.