Solve for a
a=\frac{2b}{3}+\frac{2}{x}
x\neq 0
Solve for b
b=\frac{3a}{2}-\frac{3}{x}
x\neq 0
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3xa=2bx+6
The equation is in standard form.
\frac{3xa}{3x}=\frac{2bx+6}{3x}
Divide both sides by 3x.
a=\frac{2bx+6}{3x}
Dividing by 3x undoes the multiplication by 3x.
a=\frac{2b}{3}+\frac{2}{x}
Divide 2bx+6 by 3x.
2bx+6=3ax
Swap sides so that all variable terms are on the left hand side.
2bx=3ax-6
Subtract 6 from both sides.
2xb=3ax-6
The equation is in standard form.
\frac{2xb}{2x}=\frac{3ax-6}{2x}
Divide both sides by 2x.
b=\frac{3ax-6}{2x}
Dividing by 2x undoes the multiplication by 2x.
b=\frac{3a}{2}-\frac{3}{x}
Divide 3ax-6 by 2x.
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