Solve for a
a=\frac{2b+5}{3}
Solve for b
b=\frac{3a-5}{2}
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3a=5+2b
Add 2b to both sides.
3a=2b+5
The equation is in standard form.
\frac{3a}{3}=\frac{2b+5}{3}
Divide both sides by 3.
a=\frac{2b+5}{3}
Dividing by 3 undoes the multiplication by 3.
-2b=5-3a
Subtract 3a from both sides.
\frac{-2b}{-2}=\frac{5-3a}{-2}
Divide both sides by -2.
b=\frac{5-3a}{-2}
Dividing by -2 undoes the multiplication by -2.
b=\frac{3a-5}{2}
Divide 5-3a by -2.
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