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Solve for a
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Solve for b
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3a=2b
Add 2b to both sides. Anything plus zero gives itself.
\frac{3a}{3}=\frac{2b}{3}
Divide both sides by 3.
a=\frac{2b}{3}
Dividing by 3 undoes the multiplication by 3.
-2b=-3a
Subtract 3a from both sides. Anything subtracted from zero gives its negation.
\frac{-2b}{-2}=-\frac{3a}{-2}
Divide both sides by -2.
b=-\frac{3a}{-2}
Dividing by -2 undoes the multiplication by -2.
b=\frac{3a}{2}
Divide -3a by -2.