Solve 3a^2-4x-5=0

$$3 a ^ { 2 } - 4 x - 5 = 0$$

Solve for x

$$x=\frac{3a^{2}-5}{4}$$

Steps for Solving Linear Equation

Subtract 3a^{2} from both sides. Anything subtracted from zero gives its negation.

$$-4x-5=-3a^{2}$$

Add 5 to both sides.

$$-4x=-3a^{2}+5$$

The equation is in standard form.

$$-4x=5-3a^{2}$$

Divide both sides by -4.

$$\frac{-4x}{-4}=\frac{5-3a^{2}}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$x=\frac{5-3a^{2}}{-4}$$

Divide -3a^{2}+5 by -4.

$$x=\frac{3a^{2}-5}{4}$$

Solve for a (complex solution)

$$a=-\frac{\sqrt{12x+15}}{3}$$

$$a=\frac{\sqrt{12x+15}}{3}$$

Solve for a

$$a=\frac{\sqrt{12x+15}}{3}$$

$$a=-\frac{\sqrt{12x+15}}{3}\text{, }x\geq -\frac{5}{4}$$